若数列{an}满足a1=5,an+1=(an+1)^2/2an+an/2,则其前10项和是希望能得到详尽的答案 谢谢各位~(*^◎^*)
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![若数列{an}满足a1=5,an+1=(an+1)^2/2an+an/2,则其前10项和是希望能得到详尽的答案 谢谢各位~(*^◎^*)](/uploads/image/z/15255012-12-2.jpg?t=%E8%8B%A5%E6%95%B0%E5%88%97%7Ban%7D%E6%BB%A1%E8%B6%B3a1%3D5%2Can%2B1%3D%EF%BC%88an%2B1%EF%BC%89%5E2%2F2an%2Ban%2F2%2C%E5%88%99%E5%85%B6%E5%89%8D10%E9%A1%B9%E5%92%8C%E6%98%AF%E5%B8%8C%E6%9C%9B%E8%83%BD%E5%BE%97%E5%88%B0%E8%AF%A6%E5%B0%BD%E7%9A%84%E7%AD%94%E6%A1%88+%E8%B0%A2%E8%B0%A2%E5%90%84%E4%BD%8D%7E%28%2A%5E%E2%97%8E%5E%2A%29)
若数列{an}满足a1=5,an+1=(an+1)^2/2an+an/2,则其前10项和是希望能得到详尽的答案 谢谢各位~(*^◎^*)
若数列{an}满足a1=5,an+1=(an+1)^2/2an+an/2,则其前10项和是
希望能得到详尽的答案 谢谢各位~(*^◎^*)
若数列{an}满足a1=5,an+1=(an+1)^2/2an+an/2,则其前10项和是希望能得到详尽的答案 谢谢各位~(*^◎^*)
等式两边同乘以2an,变为:2an*a(n+1)=[a(n+1)]^2*an^2
即[a(n+1)]^2-2an*[a(n+1)]+an^2=0
所以a(n+1)=an
即an=a1=5
前十项和就是50.
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