确定系数λ,使矩阵A={1 1 λ² -2 ; 1 -2 λ 1 ; -2 1 -2 λ}的秩最小确定系数λ,使矩阵A={1 1 λ² -2 ;1 -2 λ 1 ; -2 1 -2 λ}的秩最小
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![确定系数λ,使矩阵A={1 1 λ² -2 ; 1 -2 λ 1 ; -2 1 -2 λ}的秩最小确定系数λ,使矩阵A={1 1 λ² -2 ;1 -2 λ 1 ; -2 1 -2 λ}的秩最小](/uploads/image/z/15253838-62-8.jpg?t=%E7%A1%AE%E5%AE%9A%E7%B3%BB%E6%95%B0%CE%BB%2C%E4%BD%BF%E7%9F%A9%E9%98%B5A%3D%7B1+1+%CE%BB%26%23178%3B+-2+%EF%BC%9B+1+-2+%CE%BB+1+%EF%BC%9B+-2+1+-2+%CE%BB%7D%E7%9A%84%E7%A7%A9%E6%9C%80%E5%B0%8F%E7%A1%AE%E5%AE%9A%E7%B3%BB%E6%95%B0%CE%BB%2C%E4%BD%BF%E7%9F%A9%E9%98%B5A%3D%7B1+1+%CE%BB%26%23178%3B+-2+%EF%BC%9B1+-2+%CE%BB+1+%EF%BC%9B+-2+1+-2+%CE%BB%7D%E7%9A%84%E7%A7%A9%E6%9C%80%E5%B0%8F)
确定系数λ,使矩阵A={1 1 λ² -2 ; 1 -2 λ 1 ; -2 1 -2 λ}的秩最小确定系数λ,使矩阵A={1 1 λ² -2 ;1 -2 λ 1 ; -2 1 -2 λ}的秩最小
确定系数λ,使矩阵A={1 1 λ² -2 ; 1 -2 λ 1 ; -2 1 -2 λ}的秩最小
确定系数λ,使矩阵A={1 1 λ² -2 ;
1 -2 λ 1 ; -2 1 -2 λ}的秩最小
确定系数λ,使矩阵A={1 1 λ² -2 ; 1 -2 λ 1 ; -2 1 -2 λ}的秩最小确定系数λ,使矩阵A={1 1 λ² -2 ;1 -2 λ 1 ; -2 1 -2 λ}的秩最小
cosθ = (a · b)/(|a| |b|)= [(4)(- 1) + (3)(2)]/[√(4² + 3²) · √(1² + 2²)] = 2/(5√5)θ = 79.695°a - λb = (4i + 3j) - λ(- i + 2j) = (4 + λ)i + (3 - 2λ)j2a + b = 2(4i + 3j) + (- i + 2j) = 7i + 8i(a - λb) · (2a + b) = 0因为垂直[(4 + λ)i + (3 - 2λ)j] · (7i + 8i) = 0(4 + λ)(7) + (3 - 2λ)(8) = 0λ = 52/9