璁緓1,x2鏄柟绋媥虏-4x+2=0镄勪袱镙
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![璁緓1,x2鏄柟绋媥虏-4x+2=0镄勪袱镙](/uploads/image/z/15202573-61-3.jpg?t=%E7%92%81%E7%B7%931%2Cx2%E9%8F%84%26%2357883%3B%E6%9F%9F%E7%BB%8B%E5%AA%A5%E8%99%8F-4x%2B2%3D0%E9%95%84%E5%8B%AA%E8%A2%B1%E9%95%99)
璁緓1,x2鏄柟绋媥虏-4x+2=0镄勪袱镙
璁緓1,x2鏄柟绋媥虏-4x+2=0镄勪袱镙
璁緓1,x2鏄柟绋媥虏-4x+2=0镄勪袱镙
f(x)=√3sin2x-2(1-cos2x)/2
=2(sin2x*√3/2+cos2x*1/2)-1
=2(sin2xcosπ/6+cos2xsinπ/6)-1
=2sin(2x+π/6)-1
所以T=2π/2=π
-π/6
-4x+2=0
4x=2
x=2÷4
x=2分之1