1/(n+1)+1/(n+2)...+1/(2n)=4)如何证明
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1/(n+1)+1/(n+2)...+1/(2n)=4)如何证明
1/(n+1)+1/(n+2)...+1/(2n)=4)
如何证明
1/(n+1)+1/(n+2)...+1/(2n)=4)如何证明
1/(n+1)+1/(n+2)...+1/(2n)
< ∫ 1/x dx (n到2n的定积分)
= ln2n - ln n
= ln2 < 7/10
2^n/n*(n+1)
证明不等式:(1/n)^n+(2/n)^n+(3/n)^n+.+(n/n)^n
2n/(n+1)n!
(n+2)!/(n+1)!
1*N+2*(N-1)+3*(N-2)+...+N*1=1/6N(N+1)(N+2)
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n^(n+1/n)/(n+1/n)^n
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