举例说明lim(h→0)f(xo+h)-f(xo-h)\2h=f'(xo)存在,推导不出函数f(x)在x=xo处可导已知f(x)在x0处可导,则limh→0 [f(x0+h)-f(x0-h)]/2h+f'(xo).举例说明lim(h→0)f(xo+h)-f(xo-h)\2h=f'(xo)存在,推导不出
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![举例说明lim(h→0)f(xo+h)-f(xo-h)\2h=f'(xo)存在,推导不出函数f(x)在x=xo处可导已知f(x)在x0处可导,则limh→0 [f(x0+h)-f(x0-h)]/2h+f'(xo).举例说明lim(h→0)f(xo+h)-f(xo-h)\2h=f'(xo)存在,推导不出](/uploads/image/z/15008594-50-4.jpg?t=%E4%B8%BE%E4%BE%8B%E8%AF%B4%E6%98%8Elim%28h%E2%86%920%29f%28xo%2Bh%29-f%28xo-h%29%5C2h%3Df%26%23039%3B%28xo%29%E5%AD%98%E5%9C%A8%2C%E6%8E%A8%E5%AF%BC%E4%B8%8D%E5%87%BA%E5%87%BD%E6%95%B0f%28x%29%E5%9C%A8x%3Dxo%E5%A4%84%E5%8F%AF%E5%AF%BC%E5%B7%B2%E7%9F%A5f%EF%BC%88x%EF%BC%89%E5%9C%A8x0%E5%A4%84%E5%8F%AF%E5%AF%BC%2C%E5%88%99limh%E2%86%920+%5Bf%EF%BC%88x0%EF%BC%8Bh%EF%BC%89%EF%BC%8Df%EF%BC%88x0%EF%BC%8Dh%EF%BC%89%5D%EF%BC%8F2h%2Bf%27%28xo%29.%E4%B8%BE%E4%BE%8B%E8%AF%B4%E6%98%8Elim%28h%E2%86%920%29f%28xo%2Bh%29-f%28xo-h%29%5C2h%3Df%27%28xo%29%E5%AD%98%E5%9C%A8%2C%E6%8E%A8%E5%AF%BC%E4%B8%8D%E5%87%BA)
举例说明lim(h→0)f(xo+h)-f(xo-h)\2h=f'(xo)存在,推导不出函数f(x)在x=xo处可导已知f(x)在x0处可导,则limh→0 [f(x0+h)-f(x0-h)]/2h+f'(xo).举例说明lim(h→0)f(xo+h)-f(xo-h)\2h=f'(xo)存在,推导不出
举例说明lim(h→0)f(xo+h)-f(xo-h)\2h=f'(xo)存在,推导不出函数f(x)在x=xo处可导
已知f(x)在x0处可导,则limh→0 [f(x0+h)-f(x0-h)]/2h+f'(xo).举例说明lim(h→0)f(xo+h)-f(xo-h)\2h=f'(xo)存在,推导不出函数f(x)在x=xo处可导
举例说明lim(h→0)f(xo+h)-f(xo-h)\2h=f'(xo)存在,推导不出函数f(x)在x=xo处可导已知f(x)在x0处可导,则limh→0 [f(x0+h)-f(x0-h)]/2h+f'(xo).举例说明lim(h→0)f(xo+h)-f(xo-h)\2h=f'(xo)存在,推导不出
f(x)= |x| 在x=0 处,lim(h→0) (f(xo+h)-f(xo-h))/2h = lim(h→0) (h-h)/2h = 0
但 此函数在 x=0 处不可导.