(x+ 1 )*( x+2 )*(x+3) . *(x +10 )= a0+ a1*x+ a2 *((x+1)*(x+2)*(x+3)*(x+4)*.*(x+10)=a0+a1*x+a2*(x的平方 )+a3*(x的3次方 )+a4*(x的4次方 )+.+a10*(x的10次方).问a9等于多少.答案是a9 =1+ 2 +3+ 4+ 5+ 6+ 7+ 8+ 9 +10=55.请
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![(x+ 1 )*( x+2 )*(x+3) . *(x +10 )= a0+ a1*x+ a2 *((x+1)*(x+2)*(x+3)*(x+4)*.*(x+10)=a0+a1*x+a2*(x的平方 )+a3*(x的3次方 )+a4*(x的4次方 )+.+a10*(x的10次方).问a9等于多少.答案是a9 =1+ 2 +3+ 4+ 5+ 6+ 7+ 8+ 9 +10=55.请](/uploads/image/z/14412372-60-2.jpg?t=%28x%2B+1+%29%2A%28+x%2B2+%29%2A%28x%2B3%29+.+%2A%28x+%2B10+%29%3D+a0%2B+a1%2Ax%2B++a2+%2A%28%28x%2B1%29%2A%28x%2B2%29%2A%28x%2B3%29%2A%28x%2B4%29%2A.%2A%28x%2B10%29%3Da0%2Ba1%2Ax%2Ba2%2A%28x%E7%9A%84%E5%B9%B3%E6%96%B9+++++%29%2Ba3%2A%28x%E7%9A%843%E6%AC%A1%E6%96%B9+++++%29%2Ba4%2A%28x%E7%9A%844%E6%AC%A1%E6%96%B9+++++%29%2B.%2Ba10%2A%28x%E7%9A%8410%E6%AC%A1%E6%96%B9%EF%BC%89.%E9%97%AEa9%E7%AD%89%E4%BA%8E%E5%A4%9A%E5%B0%91.%E7%AD%94%E6%A1%88%E6%98%AFa9+%3D1%2B+2+%2B3%2B+4%2B+5%2B+6%2B+7%2B+8%2B++9+%2B10%3D55.%E8%AF%B7)
(x+ 1 )*( x+2 )*(x+3) . *(x +10 )= a0+ a1*x+ a2 *((x+1)*(x+2)*(x+3)*(x+4)*.*(x+10)=a0+a1*x+a2*(x的平方 )+a3*(x的3次方 )+a4*(x的4次方 )+.+a10*(x的10次方).问a9等于多少.答案是a9 =1+ 2 +3+ 4+ 5+ 6+ 7+ 8+ 9 +10=55.请
(x+ 1 )*( x+2 )*(x+3) . *(x +10 )= a0+ a1*x+ a2 *(
(x+1)*(x+2)*(x+3)*(x+4)*.*(x+10)=a0+a1*x+a2*(x的平方 )+a3*(x的3次方 )+a4*(x的4次方 )+.+a10*(x的10次方).问a9等于多少.答案是a9 =1+ 2 +3+ 4+ 5+ 6+ 7+ 8+ 9 +10=55.请问为什么.写怎么得到a9=1+ 2+ 3+ 4+ 5 +6 +7+ 8+ 9 +10=55.本题是高中关于二项式定理的题目.
(x+ 1 )*( x+2 )*(x+3) . *(x +10 )= a0+ a1*x+ a2 *((x+1)*(x+2)*(x+3)*(x+4)*.*(x+10)=a0+a1*x+a2*(x的平方 )+a3*(x的3次方 )+a4*(x的4次方 )+.+a10*(x的10次方).问a9等于多少.答案是a9 =1+ 2 +3+ 4+ 5+ 6+ 7+ 8+ 9 +10=55.请
一共有10项含有x的子项,要想得到x的9次方,必须有9项x相承,而剩下的一项只能取常数与他们相乘,这样系数就是这个常数,然后10个常数分别得到10个x的9次方,那么a9也就是这10个常数的加和.