想知道:(x 1)=x2x 1\n’;’\t’;’\a’各起什么作用f(x2)-f(x1)=loga(x2^2-ax2)-loga(x1^2-ax1)BE=BC CE=BC CA/2;CF=CA AF=CA AB/2
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![想知道:(x 1)=x2x 1\n’;’\t’;’\a’各起什么作用f(x2)-f(x1)=loga(x2^2-ax2)-loga(x1^2-ax1)BE=BC CE=BC CA/2;CF=CA AF=CA AB/2](/uploads/image/z/13950567-63-7.jpg?t=%E6%83%B3%E7%9F%A5%E9%81%93%EF%BC%9A%28x+1%29%3Dx2x+1%5Cn%E2%80%99%EF%BC%9B%E2%80%99%5Ct%E2%80%99%EF%BC%9B%E2%80%99%5Ca%E2%80%99%E5%90%84%E8%B5%B7%E4%BB%80%E4%B9%88%E4%BD%9C%E7%94%A8f%28x2%29-f%28x1%29%3Dloga%28x2%5E2-ax2%29-loga%28x1%5E2-ax1%29BE%3DBC+CE%3DBC+CA%2F2%EF%BC%9BCF%3DCA+AF%3DCA+AB%2F2)
想知道:(x 1)=x2x 1\n’;’\t’;’\a’各起什么作用f(x2)-f(x1)=loga(x2^2-ax2)-loga(x1^2-ax1)BE=BC CE=BC CA/2;CF=CA AF=CA AB/2
想知道:(x 1)=x2x 1\n’;’\t’;’\a’各起什么作用
f(x2)-f(x1)=loga(x2^2-ax2)-loga(x1^2-ax1)BE=BC CE=BC CA/2;CF=CA AF=CA AB/2
想知道:(x 1)=x2x 1\n’;’\t’;’\a’各起什么作用f(x2)-f(x1)=loga(x2^2-ax2)-loga(x1^2-ax1)BE=BC CE=BC CA/2;CF=CA AF=CA AB/2
(2x-14) / (x^2-1)
-(k-2 )x k