先化简再求值(a-1)²-a(a+1)其中a=1/6
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![先化简再求值(a-1)²-a(a+1)其中a=1/6](/uploads/image/z/13394934-54-4.jpg?t=%E5%85%88%E5%8C%96%E7%AE%80%E5%86%8D%E6%B1%82%E5%80%BC%EF%BC%88a-1%EF%BC%89%26%23178%3B-a%EF%BC%88a%2B1%EF%BC%89%E5%85%B6%E4%B8%ADa%3D1%2F6)
先化简再求值(a-1)²-a(a+1)其中a=1/6
先化简再求值(a-1)²-a(a+1)其中a=1/6
先化简再求值(a-1)²-a(a+1)其中a=1/6
(a-1)²-a(a+1)
=a²-2a+1-a²-a
=-3a+1
=-3x1/6+1
=-1/2+1
=1/2
化简,a^2+1-2a-a^2-a=-3a+1
原式=-1/2+1=1/2
化简得-2a
值为1|3
解 原式=a²-2a+1-a²-a = 1-3a 将a=1/6带入,得 原式=1-3*1/6=1/2