集合A={(x,y)丨x^2+mx-y+2=0} 集合B={(x,y)丨x-y+1=0 且0≤x≤2} 又 A∩B≠空集,求实数m的取值范围
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![集合A={(x,y)丨x^2+mx-y+2=0} 集合B={(x,y)丨x-y+1=0 且0≤x≤2} 又 A∩B≠空集,求实数m的取值范围](/uploads/image/z/13333250-2-0.jpg?t=%E9%9B%86%E5%90%88A%3D%EF%BD%9B%28x%2Cy%29%E4%B8%A8x%5E2%2Bmx-y%2B2%3D0%7D+%E9%9B%86%E5%90%88B%3D%EF%BD%9B%EF%BC%88x%2Cy%29%E4%B8%A8x-y%2B1%3D0+%E4%B8%940%E2%89%A4x%E2%89%A42%EF%BD%9D+%E5%8F%88+A%E2%88%A9B%E2%89%A0%E7%A9%BA%E9%9B%86%2C%E6%B1%82%E5%AE%9E%E6%95%B0m%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4)
集合A={(x,y)丨x^2+mx-y+2=0} 集合B={(x,y)丨x-y+1=0 且0≤x≤2} 又 A∩B≠空集,求实数m的取值范围
集合A={(x,y)丨x^2+mx-y+2=0} 集合B={(x,y)丨x-y+1=0 且0≤x≤2} 又 A∩B≠空集,求实数m的取值范围
集合A={(x,y)丨x^2+mx-y+2=0} 集合B={(x,y)丨x-y+1=0 且0≤x≤2} 又 A∩B≠空集,求实数m的取值范围
A={(x,y)丨x^2+mx-y+2=0}
= { (x,y) | y=x^2+mx+2}
B={(x,y)丨x-y+1=0 且0≤x≤2}
= {(x,y)丨y=x+1 且0≤x≤2}
A∩B≠空集, then
x^2+mx+2 = x+1
x^2+(m-1)x+1=0
for real roots
△≥0
(m-1)^2 - 4 ≥0
m^2 -2m -3 ≥0
(m-3)(m+1)≥0
-1≤m≤3
A的集合=(-m+根号下m^2-8)/2 和(-m-根号下m^2-8)/2 B的集合就求出最值(0,1)和(2,3)再求出M的集合就可以了。
集合A={(x,y)|y=-x^2+mx-1},B={(x,y)|y=3-x,0
高二数学题难死了集合A={(x,y)丨y=-x^2+mx-1},B={(x,y)丨y=3-x,0
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