1.(3a+7)(3a-7)+2a(2/3a-1)其中a=-3 2.试证明代数式(2x+3)(3x+2)-6x(x+3)+5x+3的值与x的取值无关(2)若2a次方=3,2的b'次方=6,求证b=a+1
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![1.(3a+7)(3a-7)+2a(2/3a-1)其中a=-3 2.试证明代数式(2x+3)(3x+2)-6x(x+3)+5x+3的值与x的取值无关(2)若2a次方=3,2的b'次方=6,求证b=a+1](/uploads/image/z/1333233-9-3.jpg?t=1.%283a%2B7%29%283a-7%29%2B2a%282%2F3a-1%29%E5%85%B6%E4%B8%ADa%3D-3+2.%E8%AF%95%E8%AF%81%E6%98%8E%E4%BB%A3%E6%95%B0%E5%BC%8F%EF%BC%882x%2B3%EF%BC%89%EF%BC%883x%2B2%EF%BC%89-6x%EF%BC%88x%2B3%EF%BC%89%2B5x%2B3%E7%9A%84%E5%80%BC%E4%B8%8Ex%E7%9A%84%E5%8F%96%E5%80%BC%E6%97%A0%E5%85%B3%EF%BC%882%EF%BC%89%E8%8B%A52a%E6%AC%A1%E6%96%B9%3D3%2C2%E7%9A%84b%27%E6%AC%A1%E6%96%B9%3D6%2C%E6%B1%82%E8%AF%81b%3Da%2B1)
1.(3a+7)(3a-7)+2a(2/3a-1)其中a=-3 2.试证明代数式(2x+3)(3x+2)-6x(x+3)+5x+3的值与x的取值无关(2)若2a次方=3,2的b'次方=6,求证b=a+1
1.(3a+7)(3a-7)+2a(2/3a-1)其中a=-3 2.试证明代数式(2x+3)(3x+2)-6x(x+3)+5x+3的值与x的取值无关
(2)若2a次方=3,2的b'次方=6,求证b=a+1
1.(3a+7)(3a-7)+2a(2/3a-1)其中a=-3 2.试证明代数式(2x+3)(3x+2)-6x(x+3)+5x+3的值与x的取值无关(2)若2a次方=3,2的b'次方=6,求证b=a+1
(3a+7)(3a-7)+2a(2/3a-1)其中a=-3
=[3*(-3)+7][3*(-3)-7]+2*3(2/3*3-1)
=[-9+7][-9-7]+6(2-1)
=(-16)*(-2)+6
=32+6
=38
(2x+3)(3x+2)-6x(x+3)+5x+3
=6x^2+13x+6-6x^2-18x+5x+3
=6x^2-6x^2+13x+5x-18x+3+6
=6+3
=9
经化简代数式的值与x的取值无关
2^a=3
2^b=6
6=3*2
2^b=2^a*2
2^b=2^(a+1)
所以b=a+1
(a+2)(a-2)(a二次方-a)+(2+a)(3-a)(a+3) (a+2)(a-2)(a二次方-7)+(2+a)(3-a)(a+3)
a-2a+3a-4a+5a-6a+7a-8a+9a-10a+11a.+99a-100a=
5(a*a*b-3*a*a*b)-2*(a*a*b-7*a*b*b)
[-a*(-2a)^3*(-a)^5]^7
7a+3a^2+2a-a^2+3
3a平方-2a+4a平方-7a
合并同类项:a-2a-3a+4a+5a-6a-7a+8a+9a-10a-11a+12a+……+2008a+2009a-2010a-2011a
化简a+2a-3a-4q+5a+6a-7a-8a+...2001a+2002a-2003a-2004a
因式分解:(a+2)(a-3(a²-7)+(2+a)(3-a)(a+3)
分式计算(a+1/a^2+3a+2)+(a+3/a^2+7a+12)
计算[(a^2+7a-8)/(4a-a^3)]*[(a^2-4)/(3a+24)]
计算 8a-a^3+a^2+4a^3-a^2-7a-6
化简(a+ 3)(a-3) (a-5)(a+7)-2a(a-1)
(a+3)(a-3)+(a-5)(a+7)-2a(a-1)怎么做?
-[-7a平方-5a+(2a平方-3a)+2a]-4a平方. 很急啊.
a>0,求a+a^3+a^5+a^7+.a^2n-1
a-2a-3a+4a+5a-6a-7a+8a+9a-10a-11a.+2008a+2009a-2010a-2011a如何合并同类项?
a²-3a-3a²+a²+2a-7 = a²+a²-3a²-3a+2a-7