x³-√5x²﹢﹙√5-2﹚x﹢2√5-5=0
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/04 15:00:09
![x³-√5x²﹢﹙√5-2﹚x﹢2√5-5=0](/uploads/image/z/1270490-50-0.jpg?t=x%26%23179%3B-%E2%88%9A5x%26%23178%3B%EF%B9%A2%EF%B9%99%E2%88%9A5-2%EF%B9%9Ax%EF%B9%A22%E2%88%9A5-5%3D0)
x³-√5x²﹢﹙√5-2﹚x﹢2√5-5=0
x³-√5x²﹢﹙√5-2﹚x﹢2√5-5=0
x³-√5x²﹢﹙√5-2﹚x﹢2√5-5=0
x³-√5x²﹢﹙√5-2﹚x﹢2√5-5=0
x²(x-√5)+(√5-2)(x-√5)=0
(x-√5)(x²+√5-2)=0
所以
x=√5
(x³-√5x²)+(√5-2)(x-√5)=0
x²(x-√5)+(√5-2)(x-√5)=0
(x-√5)[x²+(√5-2)]=0
x=√5 【因为√5-2>0,则:x²+√5-2=0无解】