若实数a、b、c满足条件a²+(根号a²+b+c+)c²-4a+16c+68=0,求代数式x²+2x-1的值
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![若实数a、b、c满足条件a²+(根号a²+b+c+)c²-4a+16c+68=0,求代数式x²+2x-1的值](/uploads/image/z/1241818-34-8.jpg?t=%E8%8B%A5%E5%AE%9E%E6%95%B0a%E3%80%81b%E3%80%81c%E6%BB%A1%E8%B6%B3%E6%9D%A1%E4%BB%B6a%26%23178%3B%2B%EF%BC%88%E6%A0%B9%E5%8F%B7a%26%23178%3B%2Bb%2Bc%2B%EF%BC%89c%26%23178%3B-4a%2B16c%2B68%3D0%2C%E6%B1%82%E4%BB%A3%E6%95%B0%E5%BC%8Fx%26%23178%3B%2B2x-1%E7%9A%84%E5%80%BC)
若实数a、b、c满足条件a²+(根号a²+b+c+)c²-4a+16c+68=0,求代数式x²+2x-1的值
若实数a、b、c满足条件a²+(根号a²+b+c+)c²-4a+16c+68=0,求代数式x²+2x-1的值
若实数a、b、c满足条件a²+(根号a²+b+c+)c²-4a+16c+68=0,求代数式x²+2x-1的值
a² + 根号(a²+b+c)+ c²-4a+16c+68=0
(a-2)² + 根号a²+b+c)+ (c+8)² = 0
(a-2)² = 0,根号(a²+b+c) = 0, (c+8)² = 0
a-2 = 0,a²+b+c = 0, c+8 = 0
a = 2,b =4 ,c= -8
2x^2+4x-8=0
x^2+2x-4=0
x²+2x-1 = (x^2+2x-4) + 3 = 3
3