(1)已知:x(1/y+1/z)+y(1/x+1/z)+z(1/x+1/y)+3=0,且1/x+1/y+1/z不等于0,求x+y+z的值.(2)设a>0,b>0,且满足根号a(根号a+根号b)=3根号b(根号a+5根号b),试探求a-b+根号ab/2a+3b+根号ab的值.
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![(1)已知:x(1/y+1/z)+y(1/x+1/z)+z(1/x+1/y)+3=0,且1/x+1/y+1/z不等于0,求x+y+z的值.(2)设a>0,b>0,且满足根号a(根号a+根号b)=3根号b(根号a+5根号b),试探求a-b+根号ab/2a+3b+根号ab的值.](/uploads/image/z/11958068-20-8.jpg?t=%281%29%E5%B7%B2%E7%9F%A5%3Ax%281%2Fy%2B1%2Fz%29%2By%281%2Fx%2B1%2Fz%29%2Bz%281%2Fx%2B1%2Fy%29%2B3%3D0%2C%E4%B8%941%2Fx%2B1%2Fy%2B1%2Fz%E4%B8%8D%E7%AD%89%E4%BA%8E0%2C%E6%B1%82x%2By%2Bz%E7%9A%84%E5%80%BC.%282%29%E8%AE%BEa%3E0%2Cb%3E0%2C%E4%B8%94%E6%BB%A1%E8%B6%B3%E6%A0%B9%E5%8F%B7a%28%E6%A0%B9%E5%8F%B7a%2B%E6%A0%B9%E5%8F%B7b%29%3D3%E6%A0%B9%E5%8F%B7b%28%E6%A0%B9%E5%8F%B7a%2B5%E6%A0%B9%E5%8F%B7b%29%2C%E8%AF%95%E6%8E%A2%E6%B1%82a-b%2B%E6%A0%B9%E5%8F%B7ab%2F2a%2B3b%2B%E6%A0%B9%E5%8F%B7ab%E7%9A%84%E5%80%BC.)
(1)已知:x(1/y+1/z)+y(1/x+1/z)+z(1/x+1/y)+3=0,且1/x+1/y+1/z不等于0,求x+y+z的值.(2)设a>0,b>0,且满足根号a(根号a+根号b)=3根号b(根号a+5根号b),试探求a-b+根号ab/2a+3b+根号ab的值.
(1)已知:x(1/y+1/z)+y(1/x+1/z)+z(1/x+1/y)+3=0,且1/x+1/y+1/z不等于0,求x+y+z的值.
(2)设a>0,b>0,且满足根号a(根号a+根号b)=3根号b(根号a+5根号b),试探求a-b+根号ab/2a+3b+根号ab的值.
(1)已知:x(1/y+1/z)+y(1/x+1/z)+z(1/x+1/y)+3=0,且1/x+1/y+1/z不等于0,求x+y+z的值.(2)设a>0,b>0,且满足根号a(根号a+根号b)=3根号b(根号a+5根号b),试探求a-b+根号ab/2a+3b+根号ab的值.
1)已知:x(1/y+1/z)+y(1/x+1/z)+z(1/x+1/y)+3=0,且1/x+1/y+1/z不等于0,
x(1/y+1/z)+y(1/x+1/z)+z(1/x+1/y)+3
=x/y+x/z+y/x+y/z+z/x+z/y+3
=(x/y+1+z/y)+(x/z+y/z+1)+(1+y/x+y/x)
=(x+y+z)/y+(x+y+z)/z+(x+y+z)/x
=(x+y+z)(1/x+1/y+1/z)
已知x(1/y+1/z)+y(1/x+1/z)+z(1/x+1/y)+3=0 且1/x+1/y+1/z≠0
那么(x+y+z)(1/x+1/y+1/z)=0
即(x+y+z)=0
为解
(2)设a>0,b>0,且满足根号a(根号a+根号b)=3根号b(根号a+5根号b),试探求a-b+根号ab/2a+3b+根号ab的值.
根号a(根号a+根号b)=3根号b(根号a+5根号b),
a+√(ab)=3√(ab)+15b,
a-2√(ab)-15b=0,
(√a+3√b)( √a-5√b)=0
所以√a-5√b=0,a=25b.
(a-b+根号ab)/(2a+3b+根号ab)
=(25b-b+5b)/(50b+3b+5b)
=1/2.
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第二题题目不清
x(1/y+1/z)+y(1/x+1/z)+z(1/x+1/y)+3
=x/y+x/z+y/x+y/z+z/x+z/y+3
=(x/y+1+z/y)+(x/z+y/z+1)+(1+y/x+y/x)
=(x+y+z)/y+(x+y+z)/z+(x+y+z)/x
=(x+y+z)(1/x+1/y+1/z)
已知x(1/y+1/z)+y(1/x+1/z)+z(1/...
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x(1/y+1/z)+y(1/x+1/z)+z(1/x+1/y)+3
=x/y+x/z+y/x+y/z+z/x+z/y+3
=(x/y+1+z/y)+(x/z+y/z+1)+(1+y/x+y/x)
=(x+y+z)/y+(x+y+z)/z+(x+y+z)/x
=(x+y+z)(1/x+1/y+1/z)
已知x(1/y+1/z)+y(1/x+1/z)+z(1/x+1/y)+3=0 且1/x+1/y+1/z≠0
那么(x+y+z)(1/x+1/y+1/z)=0
即(x+y+z)=0
为解
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