1.根号下【0.48(a³b²+a²b³)】 (a≥0,b≥0) 2.1/a根号下【1/a+1】(a>0)
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![1.根号下【0.48(a³b²+a²b³)】 (a≥0,b≥0) 2.1/a根号下【1/a+1】(a>0)](/uploads/image/z/11636374-22-4.jpg?t=1.%E6%A0%B9%E5%8F%B7%E4%B8%8B%E3%80%900.48%EF%BC%88a%26%23179%3Bb%26%23178%3B%2Ba%26%23178%3Bb%26%23179%3B%EF%BC%89%E3%80%91+%EF%BC%88a%E2%89%A50%2Cb%E2%89%A50%EF%BC%89+2.1%2Fa%E6%A0%B9%E5%8F%B7%E4%B8%8B%E3%80%901%2Fa%2B1%E3%80%91%EF%BC%88a%EF%BC%9E0%EF%BC%89)
1.根号下【0.48(a³b²+a²b³)】 (a≥0,b≥0) 2.1/a根号下【1/a+1】(a>0)
1.根号下【0.48(a³b²+a²b³)】 (a≥0,b≥0) 2.1/a根号下【1/a+1】(a>0)
1.根号下【0.48(a³b²+a²b³)】 (a≥0,b≥0) 2.1/a根号下【1/a+1】(a>0)
1.根号下【0.48(a³b²+a²b³)】=根号下[12/25·a²b²﹙a+b﹚=2/5·ab根号下[3a+3b]
(a≥0,b≥0)
2.1/a根号下【1/a+1】=.1/a根号下[﹙1+a﹚/a]=1/a根号下[﹙a+a²﹚/a²]=1/a·1/a根号下[a+a²]=1/a²·根号下[a+a²]
你要说清楚做什么?是化简?还是?
解之:化简如下:1.根号下[0.48(a³b²+a²b³)]=√[12/25*a²b²(a+b)]=√[3*(2/5)²a²b²(a+b)]=(2/5)ab√[3(a+b)];2.1/a根号下【1/a+1】=1/a√(1/a+1)=1/a²√(a²+a)