椭圆C:x²/a²+y²/b²=1(a>b>0)与直线x+y-1=0交于A,B两点.椭圆C:x²/a²+y²/b²=1(a>b>0)与直线x+y-1=0交于A,B两点,且以AB为直径的圆过原点.(1)求1/a²+1/b²的值(2
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![椭圆C:x²/a²+y²/b²=1(a>b>0)与直线x+y-1=0交于A,B两点.椭圆C:x²/a²+y²/b²=1(a>b>0)与直线x+y-1=0交于A,B两点,且以AB为直径的圆过原点.(1)求1/a²+1/b²的值(2](/uploads/image/z/11507964-60-4.jpg?t=%E6%A4%AD%E5%9C%86C%3Ax%26%23178%3B%2Fa%26%23178%3B%2By%26%23178%3B%2Fb%26%23178%3B%3D1%EF%BC%88a%EF%BC%9Eb%EF%BC%9E0%EF%BC%89%E4%B8%8E%E7%9B%B4%E7%BA%BFx%2By-1%3D0%E4%BA%A4%E4%BA%8EA%2CB%E4%B8%A4%E7%82%B9.%E6%A4%AD%E5%9C%86C%3Ax%26%23178%3B%2Fa%26%23178%3B%2By%26%23178%3B%2Fb%26%23178%3B%3D1%EF%BC%88a%EF%BC%9Eb%EF%BC%9E0%EF%BC%89%E4%B8%8E%E7%9B%B4%E7%BA%BFx%2By-1%3D0%E4%BA%A4%E4%BA%8EA%2CB%E4%B8%A4%E7%82%B9%2C%E4%B8%94%E4%BB%A5AB%E4%B8%BA%E7%9B%B4%E5%BE%84%E7%9A%84%E5%9C%86%E8%BF%87%E5%8E%9F%E7%82%B9.%EF%BC%881%EF%BC%89%E6%B1%821%2Fa%26%23178%3B%2B1%2Fb%26%23178%3B%E7%9A%84%E5%80%BC%EF%BC%882)
椭圆C:x²/a²+y²/b²=1(a>b>0)与直线x+y-1=0交于A,B两点.椭圆C:x²/a²+y²/b²=1(a>b>0)与直线x+y-1=0交于A,B两点,且以AB为直径的圆过原点.(1)求1/a²+1/b²的值(2
椭圆C:x²/a²+y²/b²=1(a>b>0)与直线x+y-1=0交于A,B两点.
椭圆C:x²/a²+y²/b²=1(a>b>0)与直线x+y-1=0交于A,B两点,且以AB为直径的圆过原点.
(1)求1/a²+1/b²的值
(2)若椭圆长轴长的范围为【根号5,根号6】,求椭圆离心率的取值范围
椭圆C:x²/a²+y²/b²=1(a>b>0)与直线x+y-1=0交于A,B两点.椭圆C:x²/a²+y²/b²=1(a>b>0)与直线x+y-1=0交于A,B两点,且以AB为直径的圆过原点.(1)求1/a²+1/b²的值(2
本人高三,没时间,仅提供一个思路,(X-X1)(X-X2)+(Y-Y1)(Y-Y2)=0是以点(X1,Y1)(X2,Y2)为直径的圆,又经过原点所以X1X2+Y1Y2=0.再用韦达定理和联立椭圆与直线即可求解第一问.