设二次函数f(x)=ax²-满足3f(2)=af(-2)求常数a的值.
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设二次函数f(x)=ax²-满足3f(2)=af(-2)求常数a的值.
设二次函数f(x)=ax²-满足3f(2)=af(-2)求常数a的值.
设二次函数f(x)=ax²-满足3f(2)=af(-2)求常数a的值.
f(2)=a*2²=4a
f(-2)=a*(-2)²=4a
所以
3f(2)=af(-2)
3*4a=a*4a
a=3
3*a*2*2=a*a*(-2)*(-2)
a=2