3x^2+y^2=12 x^2/4+y^2/12=1 设直线和椭圆交于点(2cosa,2√3sina) 四边形面积为 2*2cosa*2*2√3sina=θ是小于等于45°的.为什么a=45°,θ就等于60°了呢?
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![3x^2+y^2=12 x^2/4+y^2/12=1 设直线和椭圆交于点(2cosa,2√3sina) 四边形面积为 2*2cosa*2*2√3sina=θ是小于等于45°的.为什么a=45°,θ就等于60°了呢?](/uploads/image/z/11457273-57-3.jpg?t=3x%5E2%2By%5E2%3D12+x%5E2%2F4%2By%5E2%2F12%3D1+%E8%AE%BE%E7%9B%B4%E7%BA%BF%E5%92%8C%E6%A4%AD%E5%9C%86%E4%BA%A4%E4%BA%8E%E7%82%B9%282cosa%2C2%E2%88%9A3sina%29+%E5%9B%9B%E8%BE%B9%E5%BD%A2%E9%9D%A2%E7%A7%AF%E4%B8%BA+2%2A2cosa%2A2%2A2%E2%88%9A3sina%3D%CE%B8%E6%98%AF%E5%B0%8F%E4%BA%8E%E7%AD%89%E4%BA%8E45%C2%B0%E7%9A%84.%E4%B8%BA%E4%BB%80%E4%B9%88a%3D45%C2%B0%2C%CE%B8%E5%B0%B1%E7%AD%89%E4%BA%8E60%C2%B0%E4%BA%86%E5%91%A2%3F)
3x^2+y^2=12 x^2/4+y^2/12=1 设直线和椭圆交于点(2cosa,2√3sina) 四边形面积为 2*2cosa*2*2√3sina=θ是小于等于45°的.为什么a=45°,θ就等于60°了呢?
3x^2+y^2=12 x^2/4+y^2/12=1 设直线和椭圆交于点(2cosa,2√3sina) 四边形面积为 2*2cosa*2*2√3sina=
θ是小于等于45°的.为什么a=45°,θ就等于60°了呢?
3x^2+y^2=12 x^2/4+y^2/12=1 设直线和椭圆交于点(2cosa,2√3sina) 四边形面积为 2*2cosa*2*2√3sina=θ是小于等于45°的.为什么a=45°,θ就等于60°了呢?
不好意思,那天没有打完,现在已经修改过来了
因为0
天哪,我想看完整版的,原题在哪儿?
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
已知2x-y/x+3y=2,求代数式4x-2y/x+3y减4x+12y除以2x-y
已知2x-y/x+3y=2,求代数式4x-2y/x+3y减4x+12y/2x-y的值
已知2x-y/x+3y=2,求代数式4x-2y/x+3y减4x+12y/2x-y的值
12y(x-y)^2-8(x-y)^3=?
因式分解:12xy^2(y-x)+xy^3(x-y)+4x^2y(x-y)
3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2
(x+y)/2- x-y/2=6 3(x+y)=4(x-y)
x+y/3+x-y/2=6 4(x+y)-2(x-y)=40
12(x+y)^3(y-x)/【4(x+y)^2(x-y)】
2(x+y)-3(x-y)=3 ,4(x+y)+3(x-y)=15
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20
{(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20
4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6
3(x+y)-2(x-y)=11 4(x+y)+3(x-y)=9
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11