(4m^2-9n^2)/(2m-3n)是多少
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![(4m^2-9n^2)/(2m-3n)是多少](/uploads/image/z/1124451-27-1.jpg?t=%284m%5E2-9n%5E2%29%2F%282m-3n%29%E6%98%AF%E5%A4%9A%E5%B0%91)
(4m^2-9n^2)/(2m-3n)是多少
(4m^2-9n^2)/(2m-3n)是多少
(4m^2-9n^2)/(2m-3n)是多少
(4m^2-9n^2)/(2m-3n)
=(2m-3n)(2m+3n)/(2m-3n)
=2n+3m
2m+3n
28/37
答案是2m+3n
因为
(4m^2-9n^2)=(2m)^2-(3n)^2=(2m+3n)(2m-3n),
所以相除后就为以上结果