char* a[5]={"student","worker","cadre","soldier","peasant"};高手帮我解释一下谢谢#include "stdio.h"#include "string.h"main(){int i;char* a[5]={"student","worker","cadre","soldier","peasant"};char *p1,*p2;p1=p2=a[0];for(i=0;i0) p1=a[i];if(str
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/01 07:16:51
![char* a[5]={](/uploads/image/z/11034934-70-4.jpg?t=char%2A+a%5B5%5D%3D%7B%22student%22%2C%22worker%22%2C%22cadre%22%2C%22soldier%22%2C%22peasant%22%7D%3B%E9%AB%98%E6%89%8B%E5%B8%AE%E6%88%91%E8%A7%A3%E9%87%8A%E4%B8%80%E4%B8%8B%E8%B0%A2%E8%B0%A2%23include+%22stdio.h%22%23include+%22string.h%22main%28%29%7Bint+i%3Bchar%2A+a%5B5%5D%3D%7B%22student%22%2C%22worker%22%2C%22cadre%22%2C%22soldier%22%2C%22peasant%22%7D%3Bchar+%2Ap1%2C%2Ap2%3Bp1%3Dp2%3Da%5B0%5D%3Bfor%28i%3D0%3Bi0%29+p1%3Da%5Bi%5D%3Bif%28str)
char* a[5]={"student","worker","cadre","soldier","peasant"};高手帮我解释一下谢谢#include "stdio.h"#include "string.h"main(){int i;char* a[5]={"student","worker","cadre","soldier","peasant"};char *p1,*p2;p1=p2=a[0];for(i=0;i0) p1=a[i];if(str
char* a[5]={"student","worker","cadre","soldier","peasant"};高手帮我解释一下谢谢
#include "stdio.h"
#include "string.h"
main()
{
int i;
char* a[5]={"student","worker","cadre","soldier","peasant"};
char *p1,*p2;
p1=p2=a[0];
for(i=0;i0) p1=a[i];
if(strcmp(a[i],p2)
char* a[5]={"student","worker","cadre","soldier","peasant"};高手帮我解释一下谢谢#include "stdio.h"#include "string.h"main(){int i;char* a[5]={"student","worker","cadre","soldier","peasant"};char *p1,*p2;p1=p2=a[0];for(i=0;i0) p1=a[i];if(str
这一句的意思是:定义一个char类型的指针数组,也就是说,在a[5]这个数组中有5个字符型的指针元素,然后将{"student","worker","cadre","soldier","peasant"}分别赋值给这五个指针.
结果是a[0]="student",a[1]="worker",a[2]="cadre",a[3]="soldier",a[4]="pessant".