y=1+log2^x/2+(log2^x)^2的值域log2^x=t 求反解法做
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![y=1+log2^x/2+(log2^x)^2的值域log2^x=t 求反解法做](/uploads/image/z/1064370-66-0.jpg?t=y%3D1%2Blog2%5Ex%2F2%2B%28log2%5Ex%29%5E2%E7%9A%84%E5%80%BC%E5%9F%9Flog2%5Ex%3Dt+%E6%B1%82%E5%8F%8D%E8%A7%A3%E6%B3%95%E5%81%9A)
y=1+log2^x/2+(log2^x)^2的值域log2^x=t 求反解法做
y=1+log2^x/2+(log2^x)^2的值域
log2^x=t 求反解法做
y=1+log2^x/2+(log2^x)^2的值域log2^x=t 求反解法做
令log2^x=t
y=1+t/2+t^2
=(t+1/4)^2+15/16
∵t∈R
∴y∈[15/16,+∞)