c=((year-1)*365+((year-1)/4-(year-1)/100+(year-1)/400+1))%7;这是什么意思?
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![c=((year-1)*365+((year-1)/4-(year-1)/100+(year-1)/400+1))%7;这是什么意思?](/uploads/image/z/10540606-22-6.jpg?t=c%3D%28%28year-1%29%2A365%2B%28%28year-1%29%2F4-%28year-1%29%2F100%2B%28year-1%29%2F400%2B1%29%29%257%3B%E8%BF%99%E6%98%AF%E4%BB%80%E4%B9%88%E6%84%8F%E6%80%9D%3F)
c=((year-1)*365+((year-1)/4-(year-1)/100+(year-1)/400+1))%7;这是什么意思?
c=((year-1)*365+((year-1)/4-(year-1)/100+(year-1)/400+1))%7;这是什么意思?
c=((year-1)*365+((year-1)/4-(year-1)/100+(year-1)/400+1))%7;这是什么意思?
公元元年(也就是第一年)的第一天是星期1,以后的每一年与元年的差值取模7就可以算出该年的第一天是星期几.
c=[365*(year-1)+其中闰年的个数(闰年多一天)]%7+1;
c=((year-1)*365+((year-1)/4-(year-1)/100+(year-1)/400+1))%7;其中((year-1)/4-(year-1)/100+(year-1)/400就是其中闰年的个数,四年一闰,百年不闰,四百年再闰,所以4年的个数减去100年的个数在加上400年的个数就是其中闰年的个数了;
因为365=364+1;364%7=0;且后面的1可以加到去模公式前面去;所以可以化简成
c=(year+(year-1)/4-(year-1)/100+(year-1)/400)%7 .