(1+2x-4/x²-x-2)÷x+3/x²-1 先化简再求值 X=根号3
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![(1+2x-4/x²-x-2)÷x+3/x²-1 先化简再求值 X=根号3](/uploads/image/z/1024487-71-7.jpg?t=%281%2B2x-4%2Fx%26%23178%3B-x-2%29%C3%B7x%2B3%2Fx%26%23178%3B-1+%E5%85%88%E5%8C%96%E7%AE%80%E5%86%8D%E6%B1%82%E5%80%BC+X%3D%E6%A0%B9%E5%8F%B73)
(1+2x-4/x²-x-2)÷x+3/x²-1 先化简再求值 X=根号3
(1+2x-4/x²-x-2)÷x+3/x²-1 先化简再求值 X=根号3
(1+2x-4/x²-x-2)÷x+3/x²-1 先化简再求值 X=根号3
1+(2x-4)/(x^2-a-2)]/[(x+3)/(x^2-1)]
={1+2(x-2)/[(x-2)(x+1)]}(x^2-1)/(x+3)
=[1+2/(x+1)](x+1)(x-1)/(x+3)
=[x+1+2](x-1)/(x+3)
=x-1
x=√3 (根3)
原式=√3-1.