已知a²+4a+1=0,且(a四次方+ma²+1)÷(2a³+ma²+2a)=3,求m的值
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![已知a²+4a+1=0,且(a四次方+ma²+1)÷(2a³+ma²+2a)=3,求m的值](/uploads/image/z/1020822-6-2.jpg?t=%E5%B7%B2%E7%9F%A5a%26%23178%3B%2B4a%2B1%3D0%2C%E4%B8%94%EF%BC%88a%E5%9B%9B%E6%AC%A1%E6%96%B9%2Bma%26%23178%3B%2B1%EF%BC%89%C3%B7%EF%BC%882a%26%23179%3B%2Bma%26%23178%3B%2B2a%EF%BC%89%3D3%2C%E6%B1%82m%E7%9A%84%E5%80%BC)
已知a²+4a+1=0,且(a四次方+ma²+1)÷(2a³+ma²+2a)=3,求m的值
已知a²+4a+1=0,且(a四次方+ma²+1)÷(2a³+ma²+2a)=3,求m的值
已知a²+4a+1=0,且(a四次方+ma²+1)÷(2a³+ma²+2a)=3,求m的值
a^2=-4a-1
a^3=a^2*a=-4a^2-a=-4(-4a-1)-a=16a+4-a=15a+4
a^4=(a^2)^2=16a^2+8a+1=16(-4a-1)+8a+1=-56a-15
(a^4+ma^2+1)/2a^3+ma^2+2a=3
a^4+ma^2+1=6a^3+3ma^2+6a
2ma^2=-6a^3-6a+a^4+1
-8am-2m=-90a-24-6a-56a-15+1=-152a-38
2m(4a+1)=38(4a+1)
m=19
a=-2 m=5/8