如图,在平行四边形ABCD中,∠B=70°,AD至点F,延长CD至点E,连接EF,则∠E+∠F等于A:70° B:110° C:130° D:80°
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![如图,在平行四边形ABCD中,∠B=70°,AD至点F,延长CD至点E,连接EF,则∠E+∠F等于A:70° B:110° C:130° D:80°](/uploads/image/z/10157830-70-0.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E5%B9%B3%E8%A1%8C%E5%9B%9B%E8%BE%B9%E5%BD%A2ABCD%E4%B8%AD%2C%E2%88%A0B%3D70%C2%B0%2CAD%E8%87%B3%E7%82%B9F%2C%E5%BB%B6%E9%95%BFCD%E8%87%B3%E7%82%B9E%2C%E8%BF%9E%E6%8E%A5EF%2C%E5%88%99%E2%88%A0E%2B%E2%88%A0F%E7%AD%89%E4%BA%8EA%EF%BC%9A70%C2%B0+B%EF%BC%9A110%C2%B0+C%EF%BC%9A130%C2%B0+D%EF%BC%9A80%C2%B0)
如图,在平行四边形ABCD中,∠B=70°,AD至点F,延长CD至点E,连接EF,则∠E+∠F等于A:70° B:110° C:130° D:80°
如图,在平行四边形ABCD中,∠B=70°,AD至点F,延长CD至点E,连接EF,则∠E+∠F等于
A:70° B:110° C:130° D:80°
如图,在平行四边形ABCD中,∠B=70°,AD至点F,延长CD至点E,连接EF,则∠E+∠F等于A:70° B:110° C:130° D:80°
选B
对顶角相等=70°
三角形另外两个角之和=180° -70° =110°