若实数x,y满足2x²-6xy+9y²-4x+4=0,求根号y的值.
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![若实数x,y满足2x²-6xy+9y²-4x+4=0,求根号y的值.](/uploads/image/z/1008320-32-0.jpg?t=%E8%8B%A5%E5%AE%9E%E6%95%B0x%2Cy%E6%BB%A1%E8%B6%B32x%26%23178%3B-6xy%2B9y%26%23178%3B-4x%2B4%3D0%2C%E6%B1%82%E6%A0%B9%E5%8F%B7y%E7%9A%84%E5%80%BC.)
若实数x,y满足2x²-6xy+9y²-4x+4=0,求根号y的值.
若实数x,y满足2x²-6xy+9y²-4x+4=0,求根号y的值.
若实数x,y满足2x²-6xy+9y²-4x+4=0,求根号y的值.
答:
2x²-6xy+9y²-4x+4=0
(x²-4x+4)+(x²-6xy+9y²)=0
(x-2)²+(x-3y)²=0
所以:
x-2=0
x-3y=0
解得:x=2,y=2/3
所以:
√y=√(2/3)=√6/3