已知如图,圆O1、圆O2内切于点A,圆O1的直径AB交圆O2于点C,O1E垂直AB交圆O2于F点,BC=9,EF=5,则CO1=多少(求详解,最好能配图)A.9 B.13 C.14 D.16
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![已知如图,圆O1、圆O2内切于点A,圆O1的直径AB交圆O2于点C,O1E垂直AB交圆O2于F点,BC=9,EF=5,则CO1=多少(求详解,最好能配图)A.9 B.13 C.14 D.16](/uploads/image/z/10003101-69-1.jpg?t=%E5%B7%B2%E7%9F%A5%26%2359280%3B%E5%A6%82%E5%9B%BE%2C%E5%9C%86O1%E3%80%81%E5%9C%86O2%E5%86%85%E5%88%87%E4%BA%8E%E7%82%B9A%2C%E5%9C%86O1%E7%9A%84%E7%9B%B4%E5%BE%84AB%E4%BA%A4%E5%9C%86O2%E4%BA%8E%E7%82%B9C%2CO1E%E5%9E%82%E7%9B%B4AB%E4%BA%A4%E5%9C%86O2%E4%BA%8EF%E7%82%B9%2CBC%3D9%2CEF%3D5%2C%E5%88%99CO1%3D%E5%A4%9A%E5%B0%91%EF%BC%88%E6%B1%82%E8%AF%A6%E8%A7%A3%2C%E6%9C%80%E5%A5%BD%E8%83%BD%E9%85%8D%E5%9B%BE%EF%BC%89A.9+B.13+C.14+D.16)
已知如图,圆O1、圆O2内切于点A,圆O1的直径AB交圆O2于点C,O1E垂直AB交圆O2于F点,BC=9,EF=5,则CO1=多少(求详解,最好能配图)A.9 B.13 C.14 D.16
已知如图,圆O1、圆O2内切于点A,圆O1的直径AB交圆O2于点C,O1E垂直AB交圆O2于F点,
BC=9,EF=5,则CO1=多少(求详解,最好能配图)A.9 B.13 C.14 D.16
已知如图,圆O1、圆O2内切于点A,圆O1的直径AB交圆O2于点C,O1E垂直AB交圆O2于F点,BC=9,EF=5,则CO1=多少(求详解,最好能配图)A.9 B.13 C.14 D.16
选D16 吧AF ,CF分别相连 角AFC因AC为圆O2直径,故为直角90度,角CO1F为直角,角O1AF公共,中间太麻烦懒得写你应该会的……反正最后会推出三角形AFO1相似于三角形FCO1,所以设O1半径为x,得式(x-9)/(x-5)=(x-5)/x 推出x=25 故O1C=x-9=16